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Rawathb22 Aug, 2024Business

No of ways in which the 3 correct envelopes can be selected= 7C3 =35 Derangement of the remaining 4 envelopes & letters = 9 (derangement value for 4 is 9) Total No of ways of arrangement = 9 x 35= 315.No of ways in which the 3 correct envelopes can be selected= 7C3 =35 Derangement of the remaining 4 envelopes & letters = 9 (derangement value for 4 is 9) Total No of ways of arrangement = 9 x 35= 315.No of ways in which the 3 correct envelopes can be selected= 7C3 =35 Derangement of the remaining 4 envelopes & letters = 9 (derangement value for 4 is 9) Total No of ways of arrangement = 9 x 35= 315.

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